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Anonymous

I need help .

Hydroxylamine nitrate contains 29.17 mass % N, 4.20 mass % H, and 66.63 mass % O. Determine its empirical formula ?

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1 Answer

  1. Assume 100 g of this compound

    mass N = 29.17 g

    mass H = 4.20 g

    mass O = 66.63 g

    moles N = 29.17 g/ 14.0067 g/mol=2.083

    moles H = 4.20 g/ 1.008 g/mol=4.16

    moles O = 66.63 g/ 15.999 g/mol=4.16

    divide by the smallest number to get the ratio N : H : O

    4,16/ 2.083 =2 => H and O

    2.083 / 2.083 = 1 = > N

    the empirical formula is NH2O2 ( molar mass = 48.03 g/mol)

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