Anonymous I need help . Hydroxylamine nitrate contains 29.17 mass % N, 4.20 mass % H, and 66.63 mass % O. Determine its empirical formula ? Share Facebook Ad by Poxdo I thought 5.5″ length and 4.5″ girth is the average of penis….it’s not. “The frustration I had with all SCAMs on the internet and how I found the way to increase my penis size PERMANENTLY” Get It Now 1 Answer Voted Oldest Recent Eleanor Butler 0 Best Answers 57 Points View Profile Eleanor Butler Added an answer on April 16, 2020 at 10:13 am Assume 100 g of this compound mass N = 29.17 g mass H = 4.20 g mass O = 66.63 g moles N = 29.17 g/ 14.0067 g/mol=2.083 moles H = 4.20 g/ 1.008 g/mol=4.16 moles O = 66.63 g/ 15.999 g/mol=4.16 divide by the smallest number to get the ratio N : H : O 4,16/ 2.083 =2 => H and O 2.083 / 2.083 = 1 = > N the empirical formula is NH2O2 ( molar mass = 48.03 g/mol) 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerCancel replyYou must login or register to add a new answer.