Hydroxylamine nitrate contains 29.17 mass % N, 4.20 mass % H, and 66.63 mass O. If its molar mass is between 94 and 98 g/mol, what is its molecular formula?

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## Eleanor Butler

This answer was edited.Assume 100g sample

29.17 g N * 1 mol N= 2.0821 mol N

14.01g

4.20 g H * 1 mol H= 4.16667 mol H

1.008g H

66.63 g O * 1 mol O= 4.1644 mol O

16g O

N

_{2.0821}H_{4.16667}O_{4.1644}Divide by smallest

N

_{1}H_{2}O_{2}—>emperical formula weight = 48.026 g/mol(NH

_{2}O_{2})xwhere x= molecular formulaweight

empericalformula weight

=98/48.026

= Ë 2

(NH

_{2}O_{2})_{2}Molecular Formula = N

_{2}H_{4}O_{4}