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Anonymous

I need help .

Hydroxylamine nitrate contains 29.17 mass % N, 4.20 mass % H, and 66.63 mass O. If its molar mass is between 94 and 98 g/mol, what is its molecular formula?

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  1. This answer was edited.

    Assume 100g sample

    29.17 g N * 1 mol N= 2.0821 mol N
    14.01g

    4.20 g H * 1 mol H= 4.16667 mol H
    1.008g H

    66.63 g O * 1 mol O= 4.1644 mol O
    16g O

    2.0821 H 4.16667 O4.1644

    Divide by smallest

    N1H2O2 —>emperical formula weight = 48.026 g/mol

    (NH2O2)x

    where x= molecular formulaweight
    empericalformula weight
    =98/48.026
    = ˜ 2

    (NH2O2)2

    Molecular Formula = N2H4O4

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